10 questions · Form 3 Science Bab 7: Energy and Power
A sports car of mass $1000 kg$ travels at a constant velocity of $20 m s-1$. Find its kinetic energy.
Prefer reading to quizzing? All 10 questions are listed below with the answer and explanation under each one.
1. A sports car of mass $1000 kg$ travels at a constant velocity of $20 m s-1$. Find its kinetic energy.
Answer: B
$E_k = 12 m v2 = 12 × 1000 × (20)2 = 500 × 400 = 200,000 J$ (or $200 kJ$).
2. In which of the following scenarios is NO work done according to physics definition?
Answer: B
Work requires displacement in the direction of applied force ($W = F × s$). Since displacement is zero ($s = 0$), no work is done.
3. If the speed ($v$) of a moving vehicle is DOUBLED, how does its kinetic energy change?
Answer: C
Since $E_k \propto v2$, doubling the velocity increases kinetic energy by $(2)2 = 4$ times.
4. What is the rate at which work is done or energy is transferred called?
Answer: B
Power is defined as the rate of doing work ($P = Wt$).
5. What is the formula used to calculate the kinetic energy ($E_k$) of a moving object?
Answer: C
Kinetic energy of a mass $m$ moving at speed $v$ is given by $E_k = 12 m v2$.
6. A rubber bowstring is pulled back with an average force of $100 N$ by a distance of $0.4 m$. How much elastic potential energy is stored in the bowstring?
Answer: A
$E_e = 12 F x = 12 × 100 N × 0.4 m = 20 J$.
7. A simple pendulum swings back and forth between points A, B, and C (where B is the lowest point). At which position is its kinetic energy at a MAXIMUM?
Answer: B
At the lowest position (B), gravitational potential energy is converted entirely into kinetic energy, reaching maximum speed.
8. A student weighing $450 N$ climbs a staircase of vertical height $4 m$ in $6 seconds$. What is the useful power generated by the student?
Answer: B
Work $W = F × s = 450 N × 4 m = 1800 J$. Power $P = 18006 = 300 W$.
9. Calculate the gravitational potential energy possessed by a $2 kg$ book rested on a shelf $3 m$ above the floor ($g = 10 m s-2$).
Answer: D
Gravitational potential energy $E_p = mgh = 2 × 10 × 3 = 60 J$.
10. Using conservation of energy, calculate the velocity of a $0.5 kg$ ball dropped from a height of $5 m$ just before hitting the floor ($g = 10 m s-2$).
Answer: A
$mgh = 12 m v2 arrow v = √2gh = √(2 × 10 × 5) = √100 = 10 m s-1$.